Asked by | 31st Jan, 2009, 08:36: PM
Let the vertical angle be C. So, the base angles are A and B.
the internal bisector of angle A will make two equal angles of measure A/2 each.
The external bisector of the other base angle will make two equal angles of measure (180-B)/2.
Let both bisectors meet at say P.
So, angle PAB=A/2
So, in triangle PBA,
angle P+ angle PAB+angle PBA= 180 ( angle sum property)
angle P=180-(angle PAB+angle PBA)
=Half of the vertical angle C.
Answered by | 1st Feb, 2009, 10:54: AM
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