Prove that
Asked by ayushsagar
| 8th Jun, 2011,
06:54: PM
Expert Answer:
L.H.S. = 4 sinA sin (60° + A) . sin (60° ? A)
= 4sinA{sin (60° + A) . sin (60° ? A)}
= 4sinA {sin260? sin2A}
= 4sinA{3/4?sin2A} = 3sinA ?4sin3A = sin3A = R.H.S
Answered by
| 8th Jun, 2011,
03:12: PM
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