Prove that the torque acting due to a force F in the xy - plane is ?x = xFy - yFx.
Asked by ARATHI M
| 10th Jan, 2013,
12:54: PM
Expert Answer:
we know that the torque is given as:
? = r X F....r=perpendicular distance of the applied force from the fixed point,
? =torque,
F=force
here
in the xy plane
r = ix + jy
F = iFx + jFy
so, we have
? = r X F = ( ix + jy) X (iFx + jFy)
by solving further using matrix method, we get
? = ix X (iFx + jFy) - jy X (iFx + jFy)
so, finally
? = xFy - yFx
we know that the torque is given as:
? = r X F....r=perpendicular distance of the applied force from the fixed point,
? =torque,
F=force
here
in the xy plane
r = ix + jy
F = iFx + jFy
so, we have
? = r X F = ( ix + jy) X (iFx + jFy)
by solving further using matrix method, we get
? = ix X (iFx + jFy) - jy X (iFx + jFy)
so, finally
? = xFy - yFx
Answered by
| 10th Jan, 2013,
01:31: PM
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