Prove that the sum of the three angles of a triangle is 180 degree.
Asked by Aravindh Ramesh
| 29th Jun, 2013,
05:03: PM
Expert Answer:
Consider a triangle ABC. Draw line a through points A and B. Draw line b through point C and parallel to line a.
Since lines a and b are parallel, <)BAC = <)B'CA and <)ABC = <)BCA'.
It is obvious that <)B'CA + <)ACB + <)BCA' = 180 degrees.
Thus <)ABC + <)BCA + <)CAB = 180 degrees.
Consider a triangle ABC. Draw line a through points A and B. Draw line b through point C and parallel to line a.
Since lines a and b are parallel, <)BAC = <)B'CA and <)ABC = <)BCA'.
It is obvious that <)B'CA + <)ACB + <)BCA' = 180 degrees.
Thus <)ABC + <)BCA + <)CAB = 180 degrees.
Answered by
| 29th Jun, 2013,
05:14: PM
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