prove that the ratio of the perimeters of two similar triangles is the same as the ratio of their corresponding sides
Asked by | 19th Jul, 2013, 10:00: AM
Expert Answer:
We know that if two triangles are similar then the ratio of their corresponding sides are equal.
Hence, if triangle ABC is similar to triangle PQR, we have:
AB/ PQ = BC/ QR = AC/ PR
Now, using a property of ratios, we have:
AB/ PQ = BC/ QR = AC/ PR = AB+BC+CA/ PQ+QR+PR
Hence, the ratio of the perimeters of two similar triangles is the same as the ratio of their corresponding sides.
Answered by | 21st Jul, 2013, 01:22: PM
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