prove that the circle inscribed on any side of a rhombus as diamters pass through the point of intersection of its diagonals]
Asked by ayush kumar | 3rd Mar, 2011, 01:41: AM
Here is the soluiton:
Let ABCD be a rhombus whose diagonals AC and BD intersect at E. Let O be centre of the circle with diameter AB. We know diagonals of a rhombus intersect each other at right angles.
Therefore, angle AEB= 900
ie. a circle with AB as diameter which passes through E.
Answered by | 5th Mar, 2011, 05:47: PM
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