prove that the amount of water required to prepare 500 gm of 2.5% solution of glucose is 487.5gm

Asked by Saurabh Budholiya | 7th Apr, 2011, 11:12: PM

Expert Answer:

mass percentage = (mass of solute / mass of solution) * 1oo
2.5 = (mass of solute / 500) * 1oo
mass of solute i.e. glucose = 12.5 g
mass of solution = 500 g
mass of solvent i.e. water = 500 - 12.5 = 487.5 g
 

Answered by  | 4th May, 2011, 09:25: AM

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