prove that the amount of water required to prepare 500 gm of 2.5% solution of glucose is 487.5gm
Asked by Saurabh Budholiya | 7th Apr, 2011, 11:12: PM
Expert Answer:
mass percentage = (mass of solute / mass of solution) * 1oo
2.5 = (mass of solute / 500) * 1oo
mass of solute i.e. glucose = 12.5 g
mass of solution = 500 g
mass of solvent i.e. water = 500 - 12.5 = 487.5 g
Answered by | 4th May, 2011, 09:25: AM
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