prove that in a triangle Sin(sq.) B –Sin(sq.)C = sin(B+C) Sin(B-C) (sq. - square)

Asked by Rida Mukadam | 29th May, 2015, 06:30: PM

Expert Answer:

R. H. S. equals sin open parentheses B plus C close parentheses sin open parentheses B minus C close parentheses equals open parentheses sin B cos C plus cos B sin C close parentheses open parentheses sin B cos C minus cos B sin C close parentheses equals open parentheses sin squared B cos squared C minus cos squared B sin squared C close parentheses equals sin squared B open parentheses 1 minus sin squared C close parentheses minus open parentheses 1 minus sin squared B close parentheses sin squared C equals sin squared B minus sin squared B sin squared C minus sin squared C plus sin squared B sin squared C equals sin squared B minus sin squared C equals L. H. S. H e n c e comma space p r o v e d.

Answered by satyajit samal | 30th May, 2015, 11:31: PM