Prove that for a vertically thrown time of ascent is equal to time of descent
Asked by seeni2005 | 7th Sep, 2015, 09:11: PM
Let the velocity at the time of throwing be u
The time for the velocity to become zero at the highest point of flight is given by first equation of motion
Thus, t1 = u/g
Height attained, h = u2/2g ----- (uisng the second equation of motion)
Now at the time the time of descent, the time taken for the ball to come down will be:
t22 = 2h/g ----- (using the third equation of motion)
→ t2 = (u/g) ---(Since, h = u2/2g)
Thus, t1 = t2
Answered by Yashvanti Jain | 8th Sep, 2015, 10:20: AM
- 𝖉𝖊𝖋𝖎𝖓𝖊 𝖙𝖍𝖗𝖚𝖘𝖙 𝖕𝖗𝖊𝖘𝖘𝖚𝖗𝖊
- find the greatest and least pressure which a metal block of size 5cm*10cm *15cm can exert if the mass of block is 50 kg
- A wooden cuboid has a mass of 8 kg.The length , breadth and height of this wooden cuboid are 100 cm , 50 cm and 20cm respectively.Find the pressure on the floors on which this block is kept.
- A solid weighs 2.10g in air.its relative density is 8.4.how much the body will weigh in water and in a liquid of relative density 1.2.
- why does rain fall in drops and not pour all together ?
- Define thrust and pressure
- Give the units for Force, Acceleration due to gravity, Gravitational Constant and Pressure.
- Calculate the pressure exerted by a cube of side 6cm and mass 2kg kept on a table.
- Why do needles and pins have pointed tip?
- A box of mass 10 kg and dimensions 2m x 2m x 2m is kept on floor. Each of its side is reduced by half metre and its mass reduces to 6kg. Find the ratio of the pressure exerted on the floor before and after the reduction.
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number