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CBSE Class 10 Answered

prove that AB2=AC.AP + BD.BP
Asked by primetutorials | 26 Jan, 2010, 05:00: PM
answered-by-expert Expert Answer

Dear Student

In a semicircle any point on perimeter of the semicirale makes right angle at diameter .

so   ABC and ADB are right angle trialgle.

Here AC and Db forms two chords of the circle.

When two circlea are crossing eachother it ia the property of circle that

AB2 =AC.AP + BD.BP

Regards

Team Topperlearning

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