prove that AB2=AC.AP + BD.BP

Dear Student

In a semicircle any point on perimeter of the semicirale makes right angle at diameter .

so   ABC and ADB are right angle trialgle.

Here AC and Db forms two chords of the circle.

When two circlea are crossing eachother it ia the property of circle that

AB² =AC.AP + BD.BP

Regards

Team Topperlearning