prove that AB2=AC.AP + BD.BP

Asked by primetutorials | 26th Jan, 2010, 05:00: PM

Expert Answer:

Dear Student

In a semicircle any point on perimeter of the semicirale makes right angle at diameter .

so   ABC and ADB are right angle trialgle.

Here AC and Db forms two chords of the circle.

When two circlea are crossing eachother it ia the property of circle that

AB2 =AC.AP + BD.BP

Regards

Team Topperlearning

Answered by  | 26th Jan, 2010, 07:34: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.