prove that AB2=AC.AP + BD.BP
Asked by primetutorials | 26th Jan, 2010, 05:00: PM
In a semicircle any point on perimeter of the semicirale makes right angle at diameter .
so ABC and ADB are right angle trialgle.
Here AC and Db forms two chords of the circle.
When two circlea are crossing eachother it ia the property of circle that
AB2 =AC.AP + BD.BP
Answered by | 26th Jan, 2010, 07:34: PM
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