prove sinA(1+tanA)+cosA(1+cotA)=secA+cosecA
Asked by FEHMEEDAH NAZNEEN | 30th Aug, 2010, 09:33: PM
Expert Answer:
LHS
={sinA[(cosA+sinA)/cosA]}+{cosA[(cosA+sinA)/sinA}
=(cosA+sinA)[(sinA/cosA)+(cosA/sinA)]
=(cosA+sinA)[(sin2A+cos2A)/sinAcosA]
=(cosA+sinA)[1/sinAcosA]
=cosecA+secA
=RHS
Answered by | 31st Aug, 2010, 08:47: AM
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