prove: (1) cot square A.cosec square B-cot square B.cosec square A= cot squareA-cot squareB (2) 2sin square theta+cos square theta= 2 under root. 2sin theta.cos theta
Asked by sonali garg | 11th Sep, 2013, 09:15: PM
Expert Answer:
Pls ask one question at a time. The solution to your first question is as follows:
LHS
= cot2A. cosec2B - cot2B. cosec2A
= cot2A. (1 + cot2B) - cot2B. (1 + cot2A)
= cot2A + cot2A cot2B - cot2B - cot2A cot2B
= cot2A - cot2B
= RHS
Pls ask one question at a time. The solution to your first question is as follows:
LHS
= cot2A. cosec2B - cot2B. cosec2A
= cot2A. (1 + cot2B) - cot2B. (1 + cot2A)
= cot2A + cot2A cot2B - cot2B - cot2A cot2B
= cot2A - cot2B
= RHS
Answered by | 11th Sep, 2013, 10:25: PM
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