Property of a A.P.
Asked by shashwatpns | 14th Mar, 2011, 06:42: PM
Dear student,
Since pth term of an AP is q and qth term is p
Therefore, a + (p – 1)d = q (i)
and a + (q – 1)d = p (ii)
Subtracting equation (ii) from equation (i), we get,
(p – 1)d – (q – 1)d = q – p
d = -1
Substituting the value of d in (1), we get
a = p + q - 1
Now, (p+q)th term will be given by
a + (p+q-1)d = p + q - 1 + (p + q - 1)(-1) = 0
We hope that clarifies your query.
Regards,
Team
TopperLearning
Since pth term of an AP is q and qth term is p
Therefore, a + (p – 1)d = q (i)
and a + (q – 1)d = p (ii)
Subtracting equation (ii) from equation (i), we get,
(p – 1)d – (q – 1)d = q – p
Since pth term of an AP is q and qth term is p
Therefore, a + (p – 1)d = q (i)
and a + (q – 1)d = p (ii)
Subtracting equation (ii) from equation (i), we get,
(p – 1)d – (q – 1)d = q – p
a + (p+q-1)d = p + q - 1 + (p + q - 1)(-1) = 0
We hope that clarifies your query.
Regards,
Team
TopperLearning
Since pth term of an AP is q and qth term is p
Therefore, a + (p – 1)d = q (i)
and a + (q – 1)d = p (ii)
Subtracting equation (ii) from equation (i), we get,
(p – 1)d – (q – 1)d = q – p
Answered by | 14th Mar, 2011, 08:28: PM
Related Videos
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change