CBSE Class 11-science Answered

N₂ + 3 H₂   2NH₃

 According to the above equation,

  1 mole of N₂ reacts with 3 mole of H₂ to give 2 mole of NH_3.

Number of moles of N₂ = 50/28 mol = 1.786 mol

Number of moles of H₂ = 10/2 mol = 5 mol

Hence, for 1.786 mol of N₂, the moles of  H₂ required would be = (1.786 x 3) moles = 5.358 moles.

But, we have only 5 mol of H₂. Hence H₂ is the limiting reagent.

So NH₃ would be formed only from that amount of available dihydrogen.

Now,3 mole of H₂ give 2 mole of NH_3.

Therfore 5 mole of H₂ give = [(2/3) x 5] mole of NH₃

                                           = 3.33 mole of NH₃