problem

Asked by fathima12 | 4th Sep, 2011, 12:17: PM

Expert Answer:

N2 + 3 H  2NH3

 According to the above equation,

  1 mole of N2 reacts with 3 mole of H2 to give 2 mole of NH3.

Number of moles of N2 = 50/28 mol = 1.786 mol

Number of moles of H2 = 10/2 mol = 5 mol

Hence, for 1.786 mol of N2, the moles of  H2 required would be = (1.786 x 3) moles = 5.358 moles.

But, we have only 5 mol of H2. Hence H2 is the limiting reagent.

So NH3 would be formed only from that amount of available dihydrogen.

Now,3 mole of H2 give 2 mole of NH3.

Therfore 5 mole of H2 give = [(2/3) x 5] mole of NH3

                                           = 3.33 mole of NH3

Answered by  | 5th Sep, 2011, 10:43: AM

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