PROBLEM

Asked by  | 14th Mar, 2013, 09:26: PM

Expert Answer:

C2H6 + 7/2O2 -----> 2CO2 + 3H2O
Combustion of ethane gives 2 molecules of CO2 and 3 molecules of H2O. So, Z is ethane.
Z is formed on reduction of Y in the presence of nickel.
C2H4  + H2 -----> C2H6
 
ethanol with a large quantity of concentrated sulphuric acid on heating produces ethene.

CH3-CH2-OH -------> CH2=CH2 + H2O

 

Therefore, X is ethanol, Y is ethene and Z is ethane.

 
 

Answered by  | 16th Mar, 2013, 06:35: AM

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