Asked by sweetynam | 17th Feb, 2009, 10:47: PM
The resistance of one piece is 1/6 x 18 = 3 ohms, others are 6 ohms and 9 ohms.
They form a triangle with 12V connected across 9 ohms.
Now the resistance of 3 and 6 ohms are in series and this is in parallel with the 9 ohm resistor.
So total resistance is 9/2 ohms.
Current = V/i = 12/(9/2) = 8/3 A
So a current of 8/3 A will flow through each resistance.
Answered by | 18th Feb, 2009, 12:31: PM
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