problem sum
Asked by sweetynam | 18th Feb, 2009, 04:28: PM
Expert Answer:
Let the resistance of electric iron connected may be R.
We have R=R1||R2||R3
1/R= 1/100+1/50+1/500= (5+10+1)/500
R=31.25 ohms
Current through it,I=V/R=220/31.25=7.04 A
Answered by | 20th Feb, 2009, 05:41: PM
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