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CBSE Class 10 Answered

problem sum
Asked by sweetynam | 18 Feb, 2009, 04:28: PM
Expert Answer

Let the resistance of electric iron connected may be R.

We have R=R1||R2||R3

1/R= 1/100+1/50+1/500= (5+10+1)/500

R=31.25 ohms

Current through it,I=V/R=220/31.25=7.04 A

Answered by | 20 Feb, 2009, 05:41: PM

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