Asked by | 3rd Apr, 2008, 08:19: PM
first let us do question no 15, we know that flux is given by
phi= electric field(with directiion) dot (.) area vector.
in part "a" of the question,
electric field in along x axis, and area vector of the square is also along x axis,(since it is kept in Y-Z plane), so angle between the normal to the area and the electric field is zero degree, so
flux through the surface is
phi= electric field multiply by the area of the square.
so phi= 3000 multiply by 0.01
=30, N.square meter/ coulomb.
In second part. the angle between electric field and the area vector is 60 degrees, so dot product will remove by cosine of the angle between them, so net flux is
half of the flux obtained in section a
that is 15N square meter/ coulomb.
Answered by | 5th Apr, 2008, 01:57: PM
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