Asked by  | 1st Dec, 2009, 12:43: PM

Expert Answer:

The probability of husband selection ,P(H) =  1/7  probability of selecting wife P(W) =  1/5

The probability of  not selecting the husband is P(H') = 8/7

The probability of  not selecting the wife  P(W')= 4/5

(i) Probability of both of them will be selected =P(H)P(W)= 1/35

(ii) Probability of  only one  of them will be selected =P(H)P(W')+ P(H')P(W) = 8/35+4/35 = 12/35 

(iii)   Probability of  none of them selected  = P(H')P(W') = 32/35

Answered by  | 5th Dec, 2009, 11:44: AM

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