Asked by  | 9th Jun, 2008, 08:30: PM

Expert Answer:

let the no. of defective bulbs drawn from the lot = X

here we are drawing bulbs with replacements so every time peobability of drawing a defective bulb will remain same

so prob(X=x) = 6x * 24(4-x) / 304  ,where x lies between 0 to 4.

Answered by  | 10th Aug, 2008, 03:40: PM

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