PQR is a triangle and PS bisects angle QPR show that (a)PQ>QS (b)PR>RS (c)(PQ+PR)>QR
Asked by sonalagarwalagarwal544
| 3rd Jun, 2021,
08:34: AM
Expert Answer:
PSQ = sum of interior angles of Δ PQR = PRS + RPS .........................(1)
Since PS bisects QPR , we have QPS = RPS .......................(2)
From eqn.(1) and (2) PSQ = PRS + QPS
Hence PSQ > QPS , Hence in Δ PQS , we get PQ > QS ...................(3)
In similar way , we can get PR > RS ...................... (4)
By adding eqn.(3) and (4) , we get , ( PQ + PR ) > (QS + RS )
we get , ( PQ + PR ) > QS
PSQ = sum of interior angles of Δ PQR = PRS + RPS .........................(1)QPR , we have QPS = RPS .......................(2)PSQ = PRS + QPSPSQ > QPS , Hence in Δ PQS , we get PQ > QS ...................(3)
Answered by Thiyagarajan K
| 20th Sep, 2021,
02:04: PM
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