PQ is the chord of length 8 cm of a circle of radii 5 cm. The tangents at P and Q intersect at a point T. Find the length TP. Please give the solution in a simpler way.
Asked by ankit Rao | 26th Feb, 2013, 09:12: PM
Given, PQ is the chord of the circle and PT and QT are the tangents drawn at the end points of the chord PQ. PQ = 8cm and OP = 5cm.
Drawa OM perpendicular PQ and join OT
? PM = RM = 8/2 cm = 4 cm (Perpendicular from the centre of the circle to a chord bisect the chord)
Now in triangle OMP
Answered by | 27th Feb, 2013, 03:21: AM
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