PQ is the chord of length 8 cm of a circle of radii 5 cm. The tangents at P and Q intersect at a point T. Find the length TP. Please give the solution in a simpler way.

Asked by ankit Rao | 26th Feb, 2013, 09:12: PM

Expert Answer:

Given, PQ is the chord of the circle and PT and QT are the tangents drawn at the end points of the chord PQ. PQ = 8cm and OP = 5cm.

Drawa OM perpendicular PQ and join OT

? PM = RM = 8/2 cm = 4 cm  (Perpendicular from the centre of the circle to a chord bisect the chord)

Now in triangle OMP

 

Answered by  | 27th Feb, 2013, 03:21: AM

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