Asked by  | 11th Apr, 2008, 11:26: PM

Expert Answer:

p1 = V^2/R1

p2 = V^2/R2

From this R1 and R2 can be found.

Then total resitance of the circuit is R1+R2. On connecting to V, current through each resistor is same and equal to V/(R1+R2).

Power in first resistor is i^2 R1 = [V/(R1+R2)]2 R1 and similarly find power in second resistor.Then sum both values to find total power.

Answered by  | 18th Apr, 2008, 01:31: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.