Position of a particle with time is given as x = t^3 - 3t^2. Instant when it turns back is t=? 

Asked by arushidabhade | 8th Jun, 2019, 07:33: AM

Expert Answer:

position x = t3 - 3t2  ;    velocity  ( dx/dt ) = 3t2 - 6t
 
particle turning back means, velocity changes its sign
 
t dx/dt
0 0
1 -3
2 0
3 9
 
As seen from the above table, velocity changes from -ve to +ve at  t= 2+ (immediately after t =2 )

Answered by Thiyagarajan K | 8th Jun, 2019, 09:22: AM

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