Position of a particle is given as x= 10t - t^2. Particle comes to rest momentarily at t =? 

Asked by arushidabhade | 8th Jun, 2019, 07:31: AM

Expert Answer:

position x = 10t - t2 ;    velocity   dx/dt  = 10 - 2t 
 
when t = 5,  velocity is zero, hence particle comes momentarily at rest t = 5

Answered by Thiyagarajan K | 8th Jun, 2019, 09:27: AM

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