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CBSE Class 11-science Answered

Position of a particle is given as x= 10t - t^2. Particle comes to rest momentarily at t =? 
Asked by arushidabhade | 08 Jun, 2019, 07:31: AM
answered-by-expert Expert Answer
position x = 10t - t2 ;    velocity   dx/dt  = 10 - 2t 
 
when t = 5,  velocity is zero, hence particle comes momentarily at rest t = 5
Answered by Thiyagarajan K | 08 Jun, 2019, 09:27: AM
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CBSE 11-science - Physics
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CBSE 11-science - Physics
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CBSE 11-science - Physics
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CBSE 11-science - Physics
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CBSE 11-science - Physics
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CBSE 11-science - Physics
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CBSE 11-science - Physics
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CBSE 11-science - Physics
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CBSE 11-science - Physics
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CBSE 11-science - Physics
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