CBSE Class 10 Answered
Polynomials
Asked by toppin | 11 Jan, 2010, 09:47: PM
Expert Answer
Let's put x = 3.
2(3)3 + 5(3)2 - 28(3) - 15 = 0
Hence, (x-3) is a factor and 3 is a zero of the polynomial.
Using synthetic division,
(x-3)(2x2 + 11x + 5) = 0
The quadratic equation can be solved,
x = [-11±
(121-40)]/4
Hence x = -5 and -1/2.
The zeros of the given polynomial is 3, -5 and -1/2
Regards,
Team,
TopperLearning.
Answered by | 11 Jan, 2010, 10:55: PM
CBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:53: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:13: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 04:59: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by ROJAAPPA | 29 May, 2010, 12:58: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 10:52: AM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by devanshmudgal | 28 May, 2010, 07:31: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:12: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:08: PM
ANSWERED BY EXPERT
