Polynomials

Asked by toppin | 11th Jan, 2010, 09:47: PM

Expert Answer:

Let's put x = 3.

2(3)3 + 5(3)2 - 28(3) - 15 = 0

Hence, (x-3) is a factor and 3 is a zero of the polynomial.

Using synthetic division,

(x-3)(2x2 + 11x + 5) = 0

The quadratic equation can be solved,

x = [-11±(121-40)]/4

Hence x = -5 and -1/2.

The zeros of the given polynomial is 3, -5 and -1/2

Regards,

Team,

TopperLearning.

Answered by  | 11th Jan, 2010, 10:55: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.