Polynomials again!!

Asked by karanaussie | 14th Apr, 2009, 12:31: PM

Expert Answer:

since the zeroes are negatives of each other,so let them be (say) a and -a.

comparing with the standard quadratic equation,

we get,

a=4, b=-8k c=-9

We know that sum of zeroes =-b/a=-(-8k)/4=8k/4=2k

But

the sum of zeroes = a+(-a)=0

Hence

2k=0

So,

 k=0

 

Answered by  | 14th Apr, 2009, 01:06: PM

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