Asked by alfiyam | 29th Apr, 2010, 10:57: PM
p(x) when divided by (x-2), leaves 1 as remainder
=> p(x)/(x-2) = q1(x) + 1/(x-2)
where q1(x) is qotient polynomial of degree more than 1.
Similarly, p(x) when divided by (x-3), leaves 3 as remainder
=> p(x)/(x-3) = q2(x) + 3/(x-3)
where q2(x) is qotient polynomial of degree more than 1.
Now, when p(x) is divided by (x-2)(x-3) then,
(where q3(x) is the polynomial obtained by difference of q2(x) and q1(x))
Hence the remainder left by p(x) when divided by (x-3)(x-2) is (2x-3).
Answered by | 30th Apr, 2010, 12:21: AM
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