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CBSE Class 10 Answered

Polynomial
Asked by alfiyam | 29 Apr, 2010, 10:57: PM
answered-by-expert Expert Answer

Dear Student,

p(x) when divided by (x-2), leaves 1 as remainder

=> p(x)/(x-2) = q1(x) + 1/(x-2)

where q1(x) is qotient polynomial of degree more than 1.

 

Similarly, p(x) when divided by (x-3), leaves 3 as remainder

=> p(x)/(x-3) = q2(x) + 3/(x-3)

where q2(x) is qotient polynomial of degree more than 1.

 

Now, when p(x) is divided by (x-2)(x-3) then,

(where q3(x) is the polynomial obtained by difference of q2(x) and q1(x))

 

Hence the remainder left by p(x) when divided by (x-3)(x-2) is (2x-3).

 

Regards Topperlearning.

 

Answered by | 30 Apr, 2010, 12:21: AM
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