points of discontinuity

Asked by yashpinto | 28th May, 2012, 03:25: PM

Expert Answer:

For quick answer, just put the denominator equals to 0, you get
4x - x3 = 0
x(4 - x2) = 0
x = 0, 2, -2
 
Thus the function is not defined at these points and hence discountinuos.
 


 

Answered by  | 29th May, 2012, 01:04: PM

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