Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 11-science Answered

plzzzzzzz provide proper solution and reasoningg
Asked by topper getahead | 21 Jan, 2011, 12:28: AM
Expert Answer
Dear student,
 
Let m = mass of chain,
l = length of chain, l'= is the maximum length of chain that can be hung over one edge of the table.
mass per unit length = m/l
At equilibrium,
 
mue X (1-l')(m/l) X g = l' (m/l) X g,
Hence solving, we get
l' = 0.2 l
Friction = l'/l X 100 = 20%
 
Hope this helps.
Team
Topperelarning.com
Answered by | 21 Jan, 2011, 10:37: AM
CBSE 11-science - Physics
Asked by divyanshkr13 | 16 Jun, 2022, 10:25: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by kashyspalbert91 | 11 Mar, 2022, 04:11: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by shreyamishra270304 | 04 Aug, 2021, 08:32: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by shivesh242 | 26 Jul, 2021, 08:30: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by anirbanagasti2002 | 06 Jun, 2021, 09:24: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by minkukumarprasad94839483 | 30 Jan, 2021, 05:47: PM
ANSWERED BY EXPERT
Season Break Offer!
Get 60% Flat off instantly.
Avail Now
×