plzzzzzzz provide proper solution and reasoningg

Dear student,

 

Let m = mass of chain,

l = length of chain, l'= is the maximum length of chain that can be hung over one edge of the table.

mass per unit length = m/l

At equilibrium,

 

mue X (1-l')(m/l) X g = l' (m/l) X g,

Hence solving, we get

l' = 0.2 l

Friction = l'/l X 100 = 20%

 

Hope this helps.

Team

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