plzzzzzzz provide proper solution and reasoningg

Asked by topper getahead | 21st Jan, 2011, 12:28: AM

Expert Answer:

Dear student,
Let m = mass of chain,
l = length of chain, l'= is the maximum length of chain that can be hung over one edge of the table.
mass per unit length = m/l
At equilibrium,
mue X (1-l')(m/l) X g = l' (m/l) X g,
Hence solving, we get
l' = 0.2 l
Friction = l'/l X 100 = 20%
Hope this helps.

Answered by  | 21st Jan, 2011, 10:37: AM

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