plzzzzzzz ans. the question
Asked by prasadnidhi | 24th May, 2010, 04:06: PM
Expert Answer:
sec4θ (1-sin4θ) - 2tan2θ =
sec4θ (1-sin2θ)(1+sin2θ) - 2tan2θ =
sec4θ (cos2θ)(1+sin2θ) - 2tan2θ =
sec2θ (1+sin2θ) - 2tan2θ =
sec2θ + tan2θ - 2tan2θ =
sec2θ - tan2θ = 1 ... since sec2θ = 1 + tan2θ
Regards,
Team,
TopperLearning.
Answered by | 24th May, 2010, 05:30: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change