Plzzzzzz help me in this... (Refer to attachment)

Asked by jhajuhi19 | 1st May, 2019, 09:03: PM

Expert Answer:

Reduction of Au+ and Au+3   can be wriiten as-
 
Au to the power of plus plus straight e to the power of minus rightwards arrow Au space space space space space space space space horizontal ellipsis left parenthesis 1 right parenthesis
Au to the power of plus 3 end exponent plus 3 straight e to the power of minus rightwards arrow Au space space space space space horizontal ellipsis left parenthesis 2 right parenthesis

Subtracting space space equation space left parenthesis 1 right parenthesis space from space left parenthesis 2 right parenthesis
Au to the power of plus 3 end exponent plus 2 straight e to the power of minus rightwards arrow Au to the power of plus

So comma space increment straight G degree subscript 3 equals increment straight G degree subscript 2 minus increment straight G degree subscript 1
space space space space space minus 2 FE degree subscript left parenthesis bevelled fraction numerator Au to the power of plus 3 space end exponent over denominator Au to the power of plus right parenthesis end fraction end subscript equals negative 3 straight F cross times 1.40 minus left parenthesis negative 1 straight F cross times 1.69 right parenthesis space space space space space left square bracket increment straight G degree equals negative nFE degree right square bracket
space space space space space space space space space space space space space space straight E degree subscript left parenthesis bevelled fraction numerator Au to the power of plus 3 space end exponent over denominator Au to the power of plus right parenthesis end fraction end subscript equals fraction numerator 4.2 minus 1.69 over denominator 2 end fraction space space space space space space space
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 1.255 space straight V

Answered by Ravi | 2nd May, 2019, 12:35: PM