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Asked by nikitakoolkarni | 23rd Feb, 2010, 04:26: PM
AB and CD are the two direct common tangents to the two circles.
Let the two tangent meet at an external point P.
Then, PA = PC .....(1) (tangents from an external point P are equal)
Also, PB = PD .........(2) (tangents from an external point P are equal)
Now, subtracting (2) from(1), we have
PA - PB = PC - PD
AB = CD
Similarly if the two tangents are transverse common tangent.
Then we will need to add the two tangents to the two given circles to get the required result.
Please revert back if you don't get the answer.
Answered by | 24th Feb, 2010, 12:27: PM
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