Asked by dhairya | 4th May, 2009, 02:24: PM
The common difference of two AP's is same, i.e d = d'
T'100 = a'+ (100-1) d'
T100 = a + (100-1) d
T'100 - T100 = 100 = a'+ (100-1) d' - (a + (100-1) d)
100 = a' - a [Since d =d']
So the difference between their 1000th term is
T'1000 - T1000 = a'+ (1000-1) d' - (a + (1000-1) d) = a' + 999 d' - a - 999d = a' - a = 100
Answered by | 4th May, 2009, 02:58: PM
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