CBSE Class 10 Answered
plzzz help..........................circles
Asked by | 31 Oct, 2008, 06:31: PM
Expert Answer
Pa = PB (Tangents from external point)
OA = OB (Radii of same circle )
OP = OP (common)
Triangle OAP is similar to triangle OBP ( By SSS criterion)
Angle OPA = angle OPB = 60 degrees .
In Triangle OAP , the angle OAP = 90 deg (By Theorem)
sin 60 deg = AP / OP , i.e 1/2 = AP / OP
So OP = 2 AP
Answered by | 31 Oct, 2008, 09:12: PM
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