plzzz help..........................circles

Asked by  | 31st Oct, 2008, 06:31: PM

Expert Answer:

 

Pa = PB (Tangents from external point)

OA = OB (Radii of same circle )

OP = OP (common)

Triangle OAP is similar to triangle OBP ( By SSS criterion)

Angle OPA = angle OPB = 60 degrees .

In Triangle OAP , the angle OAP = 90 deg (By Theorem)

sin 60 deg = AP / OP , i.e 1/2 = AP / OP

So OP = 2 AP

Answered by  | 31st Oct, 2008, 09:12: PM

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