plzz solve this numerical
Asked by spuneet23 | 17th Jun, 2009, 04:04: PM
Since the pair of electron-proton is released, their initial velocity is zero.
Using S = ut + at2/2, and denoting by F the electrostatic force, which is qE, and same for electron and proton.
Se = aet2/2, Sp = apt2/2, ae = F/me, ap = F/mp,
Hence, Se/Sp = ae/ap = mp/me = 1837me/me = 1837,
Se = 1837 Sp
Se + Sp = 2 cm.
1837 Sp + Sp = 2 cm.
Sp = 0.001 cm = 10 μm
Sp = distance travelled by proton from it's point of release to negative plate is 10 μm.
Answered by | 17th Aug, 2009, 03:57: PM
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