plzz solve this numerical

Asked by spuneet23 | 17th Jun, 2009, 04:04: PM

Expert Answer:

Since the pair of electron-proton is released, their initial velocity is zero.

Using S = ut + at2/2, and denoting by F the electrostatic force, which is qE, and same for electron and proton.

Se = aet2/2,          Sp = apt2/2,             ae = F/me,               ap = F/mp,

Hence, Se/Sp = ae/ap = mp/me = 1837me/me = 1837,

Se = 1837 Sp

Se + Sp = 2 cm.

1837 Sp + Sp = 2 cm.

Sp = 0.001 cm = 10 μm

Sp = distance travelled by proton from it's point of release to negative plate is 10 μm.

Regards,

Team,

TopperLearning. 

Answered by  | 17th Aug, 2009, 03:57: PM

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