PLZZ ANS THIS
Asked by ridhisood
| 13th Jan, 2010,
10:12: PM
Dear Student
Say A=2θ and AC=AB=2x ==>
EAG= θ , AE=x.
Since ABC in Isosceles =
B=
C= (180-
A)/2 = (180-2θ)/2=90-θ
In any riangle a segment joining mid points of two sides is parellel to the third side
==> EF//BC ==> AEF =
C = 90-θ
In an isosceles triangle angle between equal sideas is bisecteb by line joining to the opposite side
==> GAF=θ
In the triangle AGE
A +
G+
E =180 ==>θ +
G+90-θ
==>
G= 90
So,the segment AD&EF bisect each other at right angles
Regards
Topperlearning
Answered by
| 14th Jan, 2010,
11:58: AM
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