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ICSE Class 10 Answered

plz solve
Asked by lovemaan5500 | 20 Dec, 2017, 07:08: AM
answered-by-expert Expert Answer
begin mathsize 16px style In space cyclic space quadrilateral space ABCE angle ABC plus angle AEC equals 180 degree space space space space space space space space space space space space space space Opposite space angles 132 degree plus angle AEC equals 180 degree space space space angle AEC equals 48 degree Join space BE. BE space is space straight a space diameter. In space increment BAE comma angle BAE equals 90 degree space space space space space space space space space space space space space space space space space space space space space space space space space space space space space angle BAE plus angle ABE plus angle AEB equals 180 degree angle ABE equals fraction numerator angle ABC over denominator 2 end fraction equals 66 degree 90 degree plus 66 degree plus angle AEB equals 180 degree angle AEB equals 24 degree AB equals BC equals CD angle AEB equals angle BEC equals angle CED equals 24 degree space space space space space space Inscribed space angle space in space equal space chords angle AED equals angle AEB plus angle BEC plus angle CED angle AED equals 24 degree plus 24 degree plus 24 degree angle AED equals 72 degree angle CED equals 24 degree fraction numerator Arc space CD over denominator 2 end fraction equals angle CED space space space space space space space space space space space space space space space space space space space space space space space space space Inscribed space angle Arc space CD equals 2 cross times 24 degree Arc space CD equals 48 degree Arc space CD equals angle COD equals 48 degree space space space space space end style
Answered by Sneha shidid | 20 Dec, 2017, 09:33: AM

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ICSE 10 - Maths
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