CBSE Class 12-science Answered
plz solve
Asked by | 06 Jun, 2008, 07:21: PM
sin-1 (1-x) - 2 sin-1x = /2
sin-1 (1-x) - 2 sin-1x = sin-1 (1-x) + cos-1 (1-x)
( sin-1x + cos-1x =
/2)
- 2 sin-1x = cos-1 (1-x)
Now,let sin-1x = a,then -2a = cos-1 (1-x)
or cos2a = 1 - x cos(-x) = cosx
1 - 2 sin2a = 1 - x 1 - 2x2 = 1 - x
( sin a = x )
2x2 - x = 0 x = 0 , 1/2
x = 1/2 is avoided, as it is not true.
x = 0 is the only solution.
Answered by | 07 Jun, 2008, 08:43: PM
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