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# CBSE Class 12-science Answered

plz solve
Asked by | 06 Jun, 2008, 07:21: PM

sin-1 (1-x) - 2 sin-1x  = /2

sin-1 (1-x) - 2 sin-1x  =  sin-1 (1-x)  +  cos-1 (1-x)

(  sin-1x  +  cos-1x  = /2)

- 2 sin-1x  =  cos-1 (1-x)

Now,let  sin-1x = a,then  -2a = cos-1 (1-x)

or        cos2a =  1 - x               cos(-x) = cosx

1 - 2 sin2a = 1 - x            1 - 2x= 1 - x

(  sin a = x )

2x- x = 0           x = 0 , 1/2

x = 1/2 is avoided, as it is not true.

x = 0 is the only solution.

Answered by | 07 Jun, 2008, 08:43: PM

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