CBSE Class 12-science Answered
plz solve the sum
Asked by prabhat1993 | 10 Feb, 2010, 09:35: PM
Expert Answer
Dear Student
I = S ln(1-cosx) I = S ln(1+cosx) 2I=S ln(sin^2x) I = S lnsinx Now solve this S---->Integral sign
I= S o to pi log (sin x)) dx
= 2 S o to pi/2 log (sin x)) dx-----------(1)
=S o to pi /2 log (sin x)) dx+ S o to pi/2 log (cos x)) dx
=S o tp pi/2 log (sin 2x)) dx-S o to pi/2 log 2 dx
=(1/2) S o tp pi log (sin t)) dt-pi/2 log 2
=S o tp pi/2 log (sin t)) dt-pi/2 log 2
Consider
2 S o to pi/2 log (sin t) dt = S o to pi/2 log (sin t) dt-pi/2 log 2
S o to pi/2 log (sin t) dt= -pi/2 log2
=====> S o to pi/2 log (sin t) dt= -pi log 2
I= -pi log 2 -pi/2 log2 = -3pi/2 log 2
Regards
Teram
Topperlearning.com
Answered by | 13 Feb, 2010, 11:53: AM
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