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CBSE Class 10 Answered

plz solve Q 30 . very confusing 
Asked by mdadil812777 | 10 Mar, 2017, 02:32: PM
answered-by-expert Expert Answer
size 16px To size 16px space size 16px show size 16px colon size 16px space size 16px increment size 16px PAD size 16px space size 16px is size 16px space size 16px an size 16px space size 16px isosceles size 16px space size 16px triangle
size 16px thatiis size 16px comma size 16px space size 16px to size 16px space size 16px show size 16px colon size 16px space size 16px PA size 16px equals size 16px PD
size 16px that size 16px space size 16px is size 16px comma size 16px space size 16px to size 16px space size 16px show size 16px colon size 16px space size 16px angle size 16px PDA size 16px equals size 16px angle size 16px PAD
size 16px We size 16px space size 16px know size 16px space size 16px that size 16px space size 16px angles size 16px space size 16px in size 16px space size 16px alternate size 16px space size 16px segments size 16px space size 16px are size 16px space size 16px equal size 16px space size 16px to size 16px space size 16px eachother size 16px.
size 16px So size 16px comma size 16px space size 16px using size 16px space size 16px alternate size 16px space size 16px segment size 16px space size 16px theorem size 16px comma size 16px space size 16px we size 16px space size 16px get
size 16px angle size 16px PAB size 16px equals size 16px angle size 16px DCA
size 16px But size 16px comma size 16px space size 16px angle size 16px PDA size 16px equals size 16px angle size 16px DAC size 16px plus size 16px angle size 16px DCA
size 16px rightwards double arrow size 16px angle size 16px PDA size 16px equals size 16px angle size 16px DAC size 16px plus size 16px angle size 16px PAB
size 16px rightwards double arrow size 16px angle size 16px PDA size 16px equals size 16px angle size 16px BAD size 16px plus size 16px angle size 16px PAB size 16px space size 16px. size 16px. size 16px. size 16px left parenthesis size 16px Since size 16px space size 16px angle size 16px DAC size 16px equals size 16px angle size 16px BAD size 16px space size 16px because size 16px space size 16px given size 16px space size 16px AD size 16px space size 16px bisects size 16px space size 16px the size 16px space size 16px angle size 16px space size 16px BAC size 16px right parenthesis
size 16px So size 16px comma size 16px space size 16px angle size 16px PDA size 16px equals size 16px PAD
size 16px rightwards double arrow size 16px PA size 16px equals size 16px PD
size 16px rightwards double arrow size 16px increment size 16px PAD size 16px space size 16px is size 16px space size 16px an size 16px space size 16px isosceles size 16px space size 16px triangle
 
begin mathsize 16px style Now comma space angle PAD plus angle CAD plus angle MAC equals 180 degree space... left parenthesis angles space forming space straight a space straight space line right parenthesis
rightwards double arrow angle MAC equals 180 degree space minus angle PAD minus angle CAD space space.... left parenthesis straight i right parenthesis
Also comma space angle PBA plus angle ABD equals 180 degree space... left parenthesis angles space forming space straight a space straight space line right parenthesis
rightwards double arrow angle ABD equals 180 degree minus angle PBA space.... left parenthesis ii right parenthesis
But space angle MAC equals angle ABD space... left parenthesis Since space angles space in space alternate space segments right parenthesis
rightwards double arrow 180 degree space minus angle PAD minus angle CAD equals 180 degree minus angle PBA
rightwards double arrow angle PAD plus angle CAD equals angle PBA
rightwards double arrow angle PBA equals angle PAD plus angle CAD
rightwards double arrow angle PBA equals angle PAB plus angle BAD plus angle CAD
rightwards double arrow angle PBA equals angle PAB plus angle CAD plus angle CAD
rightwards double arrow angle PBA equals angle PAB plus 2 angle CAD
rightwards double arrow angle CAD equals 1 half open parentheses angle PBA minus angle PAB close parentheses
end style
Dear Student, if you have anyother doubts, you can attend the Free Live Class today at 4 pm to 5 pm. 
Answered by Rebecca Fernandes | 10 Mar, 2017, 03:10: PM
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