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Plz solve it correctly, earlier I asked u got the wrong answer,Hopes this time correct
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Asked by vishakhachandan026 | 28 Apr, 2019, 08:49: AM
answered-by-expert Expert Answer
Meq of Basic compounds= Meq of acidic compounds
W i t h space H P h space I n d i c a t o r space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space M subscript e q end subscript space o f space N a O H space plus 1 half M subscript e q space end subscript o f space N a subscript 2 C O subscript 3 space equals space M subscript e q end subscript space o f space H C l space equals space 19.5 space cross times space 1 space equals space 19.5 W i t h space M e O H space i n d i c a t o r space space space space space space space space space space space space space space space space space space space space space space space space space space space space space M subscript e q space end subscript o f space N a O H space plus space M subscript e q space end subscript o f space N a subscript 2 C O subscript 3 space equals space 25 space cross times space 1 equals 25 S u b t r a c t i n g space t h e space t w o space e q u a t i o n space w e space g e t space minus 1 half M subscript e q end subscript space o f space N a subscript 2 C O subscript 3 space equals space minus 5.5 S o comma space M subscript e q end subscript space o f space N a subscript 2 C O subscript 3 space equals space 11 space space space space space space M subscript e q end subscript space o f space N a O H equals 14 H e n c e space w e i g h t space o f space space N a subscript 2 C O subscript 3 space p e r space l i t r e space equals fraction numerator 11 cross times 10 to the power of negative 3 end exponent over denominator 0.025 end fraction cross times 106 over 2 equals 23.32 space g L to the power of negative 1 end exponent space space space space space space space space space space space W e i g h t space o f space N a O H space p e r space l i t r e equals fraction numerator 14 cross times 10 to the power of negative 3 end exponent over denominator 0.025 end fraction cross times 40 over 1 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 560 over denominator 0.025 end fraction cross times 10 to the power of negative 3 end exponent space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 22.4 space g L to the power of negative 1 end exponent
Answered by Ravi | 29 Apr, 2019, 18:18: PM

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