Asked by narinder | 16th Feb, 2010, 06:01: PM
P = V2/R
Hence, R1 = 220x220/500 Ωand R2 = 220x220/800 Ω
1/ Since they are connected in parallel,
Current drawn by 500 W heater = V/R1 = 220/(220x220/500) = 25/11 A
Current drawn by 800 W heater = V/R2 = 220/(220x220/800) = 40/11 A
2/Resistance of 500W heater = 220x220/500 = 484/5 Ω
Resistance of 800W heater = 220x220/800 = 121/2 Ω
3/ Electric energy consumed if they operate for 2 hrs.
500 W heater will consume, (0.5kW)(2hr) = 1kWhr.
800 W heater will consume, (0.8kW)(2hr) = 1.6kWhr
Total electric energy consumed = 1 + 1.6 = 2.6 kWhr.
Answered by | 16th Feb, 2010, 06:58: PM
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