plz help me

Asked by  | 19th Feb, 2010, 06:43: AM

Expert Answer:

Drawing: Draw EF parallal to DG through D that bisect AC to G.
Prove:In triangle ADG EF|| DG and E is the midpoint of AD.
DG=2EF  .............(1)
Again In triangle ADG EF || DG
so AE/ED=AF/FG
ED/ED=AF/FG
AF=FG .................(2)
In triangle BCF BF II DG .
BD/CD=FG/CG
CD/CD=FG/CG
FG=CG ..................(3)

AC=AF+FG+GC
=AF+AF+AF
=3AF

i.e.    AF = 1 / 3 AC

Answered by  | 19th Feb, 2010, 09:19: AM

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