plz help me!
Asked by | 10th Mar, 2009, 12:33: PM
In triangles DEA and FEB,
angle DEA=angle FEB(vertically opposite angles)
angle EDA=angle EFB( alternate int angles , with DA parallel to CB i.e. CF)
triangle DEA similar to triangle FEB (AA rule)
in triangles FEB and FDC,
angle F is common
angle FEB = angle FDC(as EB and DC are parallel, so corr angles are equal)
triangle FEB similar to triangle FCD.
(I) AND (II) taken together prove the result..
Answered by | 13th Mar, 2009, 03:20: PM
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