plz help me!

Asked by  | 10th Mar, 2009, 12:33: PM

Expert Answer:

Note that,

In triangles DEA and FEB,

angle DEA=angle FEB(vertically opposite angles)

angle EDA=angle EFB( alternate int angles , with DA parallel to CB i.e. CF)


 triangle DEA similar to triangle FEB (AA rule)



 in triangles FEB and FDC,

angle F is common

angle FEB = angle FDC(as EB and DC are parallel, so corr angles are equal)


 triangle FEB similar to triangle FCD.



(I) AND (II) taken together prove the result..






Answered by  | 13th Mar, 2009, 03:20: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.