plz give me the answer for this question ???
Asked by pkartik | 13th Sep, 2008, 10:55: AM
Given: Quad ABCD such that AB and CD are the smallest and longest sides of a quadrilateral ABCD.
angle A > angle C and angle B > angle D.
Proof:Join BD. In ABD,AD> AB (AB is the smallest side of the quadrilateral ABCD)
Therefore ABD >ADB....(1)
Similarly , in triangle BDC DC>BC(Given CD is the longest sides of a quadrilateral ABCD)
So DBC > BDC.... (2)
Adding (1) and (2) , we get
Similarly join AC and from the two triangles
angle A > angle C
Answered by | 25th Sep, 2008, 08:29: PM
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