Plz answer???

Asked by  | 8th Apr, 2008, 12:01: AM

Expert Answer:

the direction of electric current will from left to right in this diagram.

now if we  assume that the  mass is uniformally distributed  in the rod , then in equilibrium the weight of the rod will equal to the tension  in the spring. now tension will equally divided in both springs so

2T=Mg.

so T=Mg/2

Now according to fleming's left hand rule  we get

IBL=Mg/2

so I=Mg/2BL

towards  right side inthe  figure.

Answered by  | 8th Apr, 2008, 05:30: PM

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