Asked by | 24th Feb, 2009, 10:16: PM
a leap year has 366 days. i.e. it has 52 weeks and 2 days extra.These 2 days can be any one of the following 7 combinations.
Mon-Tue, Tue-Wed, Wed-Thu, Thu-Fri, Fri-Sat,Sat-Sun,Sun-Mon
If we want to have only 52 tuesdays, then one of the 2 extra days can't be a tuesday.So it can be anyone of the combinationsas given below.
The total pairs are 7 , out of which the event is favourable to only 5 cases.
So the required prob is 5/7.
Answered by | 25th Feb, 2009, 09:55: AM
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