Plz answer fast as my exam is tomorrow .
Asked by | 2nd Mar, 2013, 10:23: AM
when going up: max ht it reaches:h
t=2s....to reach the highest height.
while cominbg down: it has to cover=105+20=125m
so: s=ut+1/2 at^2
so total time=5+2=7 s
Answered by | 4th Mar, 2013, 06:01: PM
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