plz ans..........fast
Asked by nikitakoolkarni
| 17th Feb, 2010,
10:23: AM
Given: AB and CD are the common tangents intersecting at E.
To prove: AB = CD
Proof: Consider E as an external point and tangent DE and AE are drawn.
Then, DE = AE ..................(1) [Since tangents from an external point are equal]
Now for the other circle CE and BE are the two tangents drawn from point E
Then CE = BC ................(2) [Since tangents from an external point are equal]
Adding (1) and (2), we get
DE + CE = AE + BC
So, CD = AB
Answered by
| 17th Feb, 2010,
11:56: AM
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